Question

2 years ago, Dilip was three times as old as his son and two years hence, twice his age will be equal to five times that of his son. Finnd their present ages.​

Answer 1

Answer:

38 and 14

Step-by-step explanation:

"D" and "s" are present ages, then

D - 2 = 3(s - 2)  

2(D + 2) = 5(s + 2)

after open () and simplifying

D - 3s = - 4

2D - 5s = 6

after multiply first equition by (- 2) and add to second one:

s = 14

Answer 2

Given :-

→ Let Dilip's son's age 2 years ago be x years.

Then, Dilip's age 2 years ago = ( 3x ) years

Thus , the son's age 2 years hence (x + 4) years.

Dilip's age 2 years hence (3x + 4) years.

→ 2 ( 3x + 4 ) = 5 ( x + 4 )

→ 6x + 8 = 5x +20

→ x = 12.

∴ Dilip's son's age 2 years ago = 12 years and Dilip's age 2 years ago = 36 years.

∴ son's present age = 14 years, and

Dilip's present age = 38 years.

Thank You!