Question

2 years ago Dilip was three times as old as his son and two years hence twice his age will be equal to five times that of his son find their present ages.

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Let Dilips son's age 2years ago be X year's.

Then, Dilips age 2years ago =(3x) years

The son's age 2years hence =(X+4)years

Dilips age 2years hence=(3x+4) years

2(3x+4)=5(X+4)

=6x +8=5x+20

=6x-5x=20-8

=X=12

Dilips son's age 2years ago =12years

And Dilips age 2years ago =3*12=36years

Son's present age= 14years and Dilips present age

=3x+4

=3*12+4

=38years

Now, Let's Check the solution:

As obtained the son's present age is 14years and Dilips present age is 38years

(1)Son's age 2years age

=14-2

=12 years

Dilips age 2years ago

=38-2

=36 years

2years ago, Dilips age =3*(son's age)

Thus ,the first condition is verified.

(2) Son's age 2years hence

=14+2

=16years

Dilips age 2 years hence

=38+2

=40years

2years hence

2*(Dilips age)=2*40=80years

5*(son's age)=5*16=80years

2years hence

2*(Dilips age)=5*(son's age)

Thus ,the second condition is also verified

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