Question

2 years ago Dilip was three times as old as his son and two years hence twice of his age will be equal to five times that of his son find their present ages

Answer 1

please have a careful look I hope it helps

Answer 2

Given :-

→ Let Dilip's son's age 2 years ago be x years.

Then, Dilip's age 2 years ago = ( 3x ) years

Thus , the son's age 2 years hence (x + 4) years.

Dilip's age 2 years hence (3x + 4) years.

→ 2 ( 3x + 4 ) = 5 ( x + 4 )

→ 6x + 8 = 5x +20

→ x = 12.

∴ Dilip's son's age 2 years ago = 12 years and Dilip's age 2 years ago = 36 years.

∴ son's present age = 14 years, and

Dilip's present age = 38 years.

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