Question

2 years ago Dilip was three times as old as his son and two years hence twice his age will be equal to 5 that of his son find their present age

Answer 1

age of dilip=x
age of son =y
2 years ago
(x-2)=3(y-2)
x-3y=-4
2 years hence
this is equation if it is 5 times
(x+2)2=5(y+2)
and if it is 5 more then
(x+2)2=y+7

Answer 2

Given :-

→ Let Dilip's son's age 2 years ago be x years.

Then, Dilip's age 2 years ago = ( 3x ) years

Thus , the son's age 2 years hence (x + 4) years.

Dilip's age 2 years hence (3x + 4) years.

→ 2 ( 3x + 4 ) = 5 ( x + 4 )

→ 6x + 8 = 5x +20

→ x = 12.

∴ Dilip's son's age 2 years ago = 12 years and Dilip's age 2 years ago = 36 years.

∴ son's present age = 14 years, and

Dilip's present age = 38 years.

Thank You!