Question

2 years ago Dilip was three times old as his son and 2 years hence twice his age will be equal to 5 times that of his son find their present ages

Answer 1

Heya !!!



Let the present age of dilip be X years and his son be Y years.




Before 2 years age of dilip = ( X-2) years.



Before 2 years age of his son = ( Y-2) years.



According to question,



( X -2) = 3 ( Y-2)




X - 2 = 3Y -6


X - 3Y = -6 +2




X - 3Y = -4 -------(1)



After 2 years dilip age = ( X+2) years




After 2 years age of his son = ( Y+2) years



According to question,



2( X +2) = 5 ( Y+2)




2X + 4 = 5Y + 10



2X -5Y = 10 -4


2X -5Y = 6 -------(2)



from equation (1) we get,



X - 3Y = -4



X = -4+3Y -------(3)


Putting the value of X in equation (2)




2X - 5Y = 6


2 × ( -4 + 3Y) -5Y = 6



-8 + 6Y -5Y = 6





Y = 6+8


Y = 14 years


Putting the value of Y in equation (3)


X = -4 + 3Y



X = -4 + 3 × 14 = -4 +42 = 38 years.



Age of dilip = X = 42 years



And,


Age of his son = Y = 14 years.





HOPE IT WILL HELP YOU....... :-)

Answer 2

I hope it will help you