Question

2 years ago father was 3 times as old as his son and 2 years hence twice his age will be equal to 5 times that of his son find their present ages

Answer 1

Father's age=x
Son's age=y
x-2=3(y-2)
x-2=3y-6
x-3y=-4
2(x+2)=5(y+2)
2x+4=5y+10
2x-5y=6
2x-6y=-8
y=14
x=38
Father's age is 38 and son's age is 14.