2 years ago father was five times as old as his son two years later his age will be 8 more than three times the age of his son find the present ages of father and son
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Hope this may help....
let son's age=x yrs
2 yrs ago,
son's age=(x-2)yrs.
father's age=5(x-2)yrs.
2 yrs later,
ATQ,
5(x-2)=8+3(x-2)
=8+3x-6
5x-10=3x+2
2x=12
x=6
therefore,
son's age=x-2
=4yrs
father's age=5x-10
=20yrs. Ans
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