Math, asked by Siakhan1393, 1 year ago

2 years ago father was five times as old as his son two years later his age will be 8 more than three times the age of his son find the present ages of father and son

Answers

Answered by Dipta516
1

Hope this may help....

let son's age=x yrs

2 yrs ago,

son's age=(x-2)yrs.

father's age=5(x-2)yrs.

2 yrs later,

ATQ,

5(x-2)=8+3(x-2)

=8+3x-6

5x-10=3x+2

2x=12

x=6

therefore,

son's age=x-2

=4yrs

father's age=5x-10

=20yrs. Ans

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