Question

2 years ago father was three times as old as his son and two years hence twice his age will be equal to 5 times that of his son find their present age​

Answer 1

Answer:

SON'S PRESENT AGE : 14 years.

FATHER'S PRESENT AGE: 38 years.

Explanation:

Let son's age = x

Two years ago son's age= x-2.

His Father's age at that time = 3(x-2).

Present age of Father = 3x-6+2=3x-4

Two years hence father's age=3x-4+2=3x-2.

Two years hence son's age = x+2.

Given :-5*(x+2)=2*(3x-2)

5x + 10= 6x - 4

10+4=6x-5x

14=x

SON'S PRESENT AGE : 14 years.

FATHER'S PRESENT AGE: 38 years.

Answer 2

Answer:

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