Math, asked by Maahi7102007, 7 months ago

2 years ago father was three times as old as his son and two years hence twice his age will be equal to five times this of his son.find the present age​

Answers

Answered by amansharma264
29

EXPLANATION.

2 years,ago father was thrice as old as his

son.

=> Let the age of son = x

=> two years ago son age = x - 2

=> father age is thrice as old as his son.

=> 3 ( x - 2 )

=> present age of father = 3x - 6 + 2

=> 3x - 4

Two, years hence

=> age of father = 3x - 4 + 2 = 3x - 2

=> age of son = x + 2 .

twice his age will be 5 times this of his son.

=> 5 ( x + 2 ) = 2 ( 3x - 2 )

=> 5x + 10 = 6x - 4

=> 14 = x

Therefore,

present age of son = x = 14 years.

present age of father = 3x - 4 = 3(14) - 4

=> 38 years.

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