2 years ago if father was 5 tkmes as old as his son two years later from today his age will be 8 years more than three times the age of his son find fhere present age
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Correct question.
2 years ago a father was 5 times as old as his
son , 2 years later his son will be 8 years more
than three times the age of son. Find their
present ages.
EXPLANATION.
To find present ages.
according to the question,
Let the age of father = x years.
Let the age of son = y years.
Two years ago,
age of father = ( x - 2 ) years.
age of son = ( y - 2 ) years.
Two years later,
age of father = ( x + 2 ) years.
age of son = ( y + 2 ) years.
According to the condition.
Case = 1
=> x - 2 = 5 ( y - 2 )
=> x - 2 = 5y - 10
=> x - 5y = -8 .....(1)
Case = 2
=> x + 2 = 3 ( y + 2 ) + 8
=> x + 2 = 3y + 6 + 8
=> x - 3y = 12 ...... (2)
From equation (1) and (2) we get,
=> - 2y = -20
=> y = 10
put the value of y = 10 in equation (2)
we get,
=> x - 30 = 12
=> x = 42
Therefore,
present age of father = 42 years.
present age of son = 10 years.
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