Question

2 years ago my age was 4×1/2 times the age of my son. Six years ago, my age was
wice the square of the age of my son. What is the present age of my son ?
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Answer 1

Step-by-step explanation:

let the present age of son be x years ,

and, present age of father = y years.

then, y-2 = 2(x-2)

= 2x - y= 2

again, y-6 = 2(x-6)²

= y-6 = 2(x² - 12x +36)

= y-6 = 2x² - 24x +72

= 2x² -24x -y +78 = 0