Question

2 years ago, my age was 4
1/2 times the
age
of my son then. 6 years ago,
2
my age was twice the square of the age of my son then. Find the present
age of my son.​

Answer 1

Answer:

let the age of son is x

according to the question

2 year ago, father's age is 41x/2

and 6 year ago , father's age is 2x^2

for present age of his father is

41x/2 +2 = 2x^2 + 6

41x+4/2. = 2x^2 + 6

41x + 4. = 4x^2 + 12

4x^2 - 41 x +8 = 0

from now find the value of x