Math, asked by nidhivermakh, 1 year ago

2 years ago my brother age was 2 times that of my age. At present the sum of my brother's age & that of mine is 51 years. what is my brother's present age?

Answers

Answered by littyissacpe8b60
0

two years before

my age = x

my brother's age = 2x

Present

my age = x + 2

Brother's age = 2x + 2

x + 2 + 2x +2 = 51

3x = 51 - 4 = 47

x = 47/3 = 15.67

Present age of brother = 2(15.67) + 2 = 31.34 + 2 = 33years

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