2 years ago salim was thrice as old as his daughter and 3 years later he will be 4 years older than twice her age how old are they now
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Solution:-
Let the age of Salim be x years.
& Age of His Daughter's age be y years.
2 years ago,
Age of Salim = (x-2)
Age of his Daughter= (y-2)
A.T.Q.
(x-2) = 3(y-2)
=> x = 2 + 3y -6
=> x = 3y -4__________(1).
3 years later,
Age of Salim = (x+3)
Age of his Daughter= (y+3)
A.T.Q.
(x+3)= 2(y+3) +2
=> x + 3 = 2y + 6 + 2
=> 3y - 4 = 2y + 8 (from eq 1.)
=> 3y -2y = 8+4
=> y = 12
Putting y=12 in eq.1
x = 3y - 4
=> x = 3×12 -4
=> x = 36 - 4
=> x = 32 years.
Hence,
Salim's Age = 32 yrs.
& His Daughter's Age = 12 years.
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