Math, asked by skr512181, 5 months ago

2 years ago the age of father was 3and half times of the age of his daughter 6 years hence the age of father will be 10 years more than the twice of the age of his daughter. find their present ages.​

Answers

Answered by Anonymous
2

\blue{\bold{\underline{\underline{Answer:}}}}

 \:\:

 \green{\underline \bold{\tt{Given :-}}}

 \:\:

  • 2 years ago the age of father was 3 and half times of the age of his daughter

 \:\:

  • 6 years hence the age of father will be 10 years more than the twice of the age of his daughter

 \:\:

 \red{\underline \bold{\tt{To \: Find :-}}}

 \:\:

  • Their present ages

 \:\:

\large{\orange{\underline{\tt{Solution :-}}}}

 \:\:

  • Let the present age of father be "f"

  • Let the present age of daughter be "d"

 \:\:

 \underline{\bold{\texttt{Father's age 2yrs ago :}}}

 \:\:

⭕ f - 2

 \:\:

 \underline{\bold{\texttt{Daughter's age 2yrs ago :}}}

 \:\:

⭕ d - 2

 \:\:

 \purple{\underline \bold{According \: to \: the \ question :}}

 \:\:

2 years ago the age of father was 3 and half times of the age of his daughter

 \:\:

 \bf\boxed { 3 \ and \ half = 3\dfrac {1 } { 2 } = \dfrac { 7 } { 2 }}

 \:\:

 \sf \longmapsto f - 2 = \dfrac { 7 } { 2 } \times (d - 2)

 \:\:

 \sf \longmapsto f - 2 = \dfrac { 7d } { 2 } - 7

 \:\:

 \sf \longmapsto f - 2 = \dfrac { 7d - 14 } { 2 }

 \:\:

 \sf \longmapsto 2f - 4 = 7d - 14

 \:\:

 \sf \longmapsto 2f - 7d = -10 -----(1)

 \:\:

 \underline{\bold{\texttt{6 yrs hence age of father :}}}

 \:\:

⭕ f + 6

 \:\:

 \underline{\bold{\texttt{6 yrs hence age of daughter :}}}

 \:\:

⭕ d + 6

 \:\:

6 years hence the age of father will be 10 years more than the twice of the age of his daughter

 \:\:

 \sf \longmapsto f + 6 = 2(d + 6) + 10

 \:\:

 \sf \longmapsto f + 6 = 2d + 12 + 10

 \:\:

 \sf \longmapsto f + 6 = 2d + 22

 \:\:

 \sf \longmapsto f - 2d = 16 -------(2)

 \:\:

 \underline{\bold{\texttt{Multiplying equation (2) by 2 }}}

 \:\:

 \sf \longmapsto 2f - 4d = 32 ------(3)

 \:\:

 \underline{\bold{\texttt{Equation (3) - (1) }}}

 \:\:

 \sf \longmapsto 2f - 4d -( 2f - 7d ) = 32 - (-10)

 \:\:

 \sf \longmapsto 3d = 42

 \:\:

 \sf \longmapsto d = \dfrac { 42 } { 3 }

 \:\:

➳ d = 14

 \:\:

 \underline{\bold{\texttt{Putting d = 14 in (2) }}}

 \:\:

➳ f - 2d = 16

 \:\:

➳ f - 2(14) = 16

 \:\:

➳ f - 28 = 16

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➳ f = 44

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  • Hence the the present ages of daughter and father is 14 & 44 respectively
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