2 years ago the age of father was 3and half times of the age of his daughter 6 years hence the age of father will be 10 years more than the twice of the age of his daughter. find their present ages.
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- 2 years ago the age of father was 3 and half times of the age of his daughter
- 6 years hence the age of father will be 10 years more than the twice of the age of his daughter
- Their present ages
- Let the present age of father be "f"
- Let the present age of daughter be "d"
⭕ f - 2
⭕ d - 2
2 years ago the age of father was 3 and half times of the age of his daughter
-----(1)
⭕ f + 6
⭕ d + 6
6 years hence the age of father will be 10 years more than the twice of the age of his daughter
-------(2)
------(3)
➳ d = 14
➳ f - 2d = 16
➳ f - 2(14) = 16
➳ f - 28 = 16
➳ f = 44
- Hence the the present ages of daughter and father is 14 & 44 respectively
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