2 years father was three times as old as his son and two year and twice his age will be equal to 5 time that of his son find the present age
Answers
Answered by
2
Answer:
SON'S PRESENT AGE : 14 years.
FATHER'S PTESENT AGE: 38 years
Step-by-step explanation:
Let son's age = x
Two years ago son's age= x-2.
His Father's age at that time = 3(x-2).
Present age of Father = 3x-6+2=3x-4
Two years hence father's age=3x-4+2=3x-2.
Two years hence son's age = x+2.
Given :-5*(x+2)=2*(3x-2)
5x + 10= 6x - 4
10+4=6x-5x
14=x
SON'S PRESENT AGE : 14 years.
FATHER'S PTESENT AGE: 38 years
PLZ MARK AS BRAINLIEST
Similar questions