2 years later a father will 8 years more than 3 times the age of the son.Taking the present age of father and son as x and y respectively . write a linear equation .... please guys answrr it fast its really very urgent .
Answers
Answer:
Let the present ages of father and son be x yr and y yr, respectively.
Two years later,
Age of father = (x + 2) yr and age of son = (y + 2) yr
According to the question,
Age of father after two years
= 3 (Age of son after two years) + 8
x + 2 = 3(y + 2)+8 =x + 2 = 3y+6+8
x - 3y -12 = 0
which is the required linear equation in two variables.
To draw the graph, we need atleast two solutions of the above equation.
Now, the above equation can be written as
x = 3y +12 ,…(i)
When y = 4,then x = 3x4+12 = 12 +12 =24
When y = 8,then x = 3x8+12 =24+12 = 36
Thus, we have the following table
image
Here, we get the points 4(24, 4) and 6(36, 8). Now, plot the points on the graph paper and join them to get a line AB, which represents the required graph.
image
Now, taking point y=10 on Y axis, draw a line parallel to X-axis, which meets the line at point C and from point C, draw a perpendicular, which intersects X-axis at 42 units distance from Y-axis.
Thus, we get point C(42,10), i.e. when son’s age is 10 yr, then the age of father is 42 yr.
not sure though
Answer:
The required linear eq is x-3y -12 = 0
Step-by-step explanation:
Let father's and son's age be x and y respectively
Given:
After 2 yrs,
=> x+2= 8+ 3(y+2)
=> x+2= 8+3y+6
=> x+2= 3y +14
=> x-3y= 12
=> x-3y -12 = 0