Question

2 yellow balls, 3 green balls & 2 blue balls are present in a container. 2 balls are drawn in a random way. what is the probability that none of them is blue?

Answer 1

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Answer 2

Answer: Probability that none of them is blue is $\dfrac{10}{21}$

Step-by-step explanation:

Since we have given that

Number of yellow balls = 2

Number of green balls = 3

Number of blue balls = 2

We need to find the probability if 2 balls are drawn then, none of them is blue.

so, our probability becomes,

$\dfrac{^5C_2}{^7C_2}\\\\=\dfrac{10}{21}$

Hence, probability that none of them is blue is $\dfrac{10}{21}$