Question

2. Zeroes of the polynomial x2-5 are (A) 1,5 (B) -5,1 (C). -√5,√5 (D) 1√5​

Answer 1

Answer:

C] -√5, √5

Step-by-step explanation:

Given Quadratic equation → x² - 5

Procedure:

For finding the zeroes of the polynomial, equate the polynomial to zero and solve for x.

Solution:

x² - 5 = 0

Adding 5 on both sides,

x² - 5 + 5 = 0 + 5

⇒ x² = 5

Taking square root on both sides,

√x² = √5

⇒ x = ± √5

∴ The value of x can be √5 or -√5