Question

2: Zn- HCl on treatment with ethyl iodide
gives
1
Butane
N
ethyl chloride
3
butyl chloride
4
ethane.​

Answer 1

Answer:

The reaction takes place as:

C

2

H

5

−I+2[H]

Zn−Cu,C

2

H

5

−OH

C

2

H

6

+HI

Answer 2

Zn-HCl on treatment with ethyl iodide  gives (4) Ethane.

• Ethyl iodide is reacted with Zinc couple in the presence of ethyl alcohol to produce ethane.
• In this chemical reaction, ethyl iodide is reduced to ethane along with formed iodides as by-products.
• The nascent hydrogen formed by the reaction between zinc and HCl acid reduces ethyl chloride to ethane.