Question

20. (1+i)^8 + (1-i)^8​

Answer 1

Answer:

32

Step-by-step explanation:

(1+i)^8=((1+i)^2)^4)

=(1-1+2*1*-1)^4

=(-2)^4

=16

(1-i)^8=((1-i)^2)^4

=(1-1-(2*1*-1))^4

=(0-(-2))^4

=2^4

=16

Therefore (1+i)^8+(1-i)^8 =16+16 = 32

Hope this helps