Question

20.
10. The 17th term of an AP exceeds its 10th term by 7. Find the common difference
11. Which term of the AP:3, 15, 27, 39, ... will be 132 more than its 54th term?​

Answer 1

Answer:

a+16d_a_9d=7

7d =7

d=1

easy problem

Answer 2

Answer:

10.

a17-a10=7

a+16d-(a+9d)=7

a+16d-a-9d=7

7d=7

d=1

11.

a=3,d=15-3

=12

a54=a+53d

=3+53(12)

=3+636

=639

639+132=771

771=3+(n-1)12

771 =3+12n-12

771=12n-9

771+9=12n

780=12n

n=780/12

n=65

Hence 65th term is 132 more than its 54th term.

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