Question

20
2. 10.6 g of a substance of molecular weight 106
was dissolved in 100 ml. 10 ml of this solution
was pipetted out into a 1000 ml flask and made
up to the mark with distilled water. The
molarity of the resulting solution is(method please)

1) 1 M
2) 10-2 M
3) 10-3
4) 10-4 M​

Answer 1

ANSWER :

Initial molarity-  

=  

106

10.6

​  

×  

V(ml)

1000

​  

 

=  

106

10.6

​  

×  

100

1000

​  

 =1M

Now,  M  

1

​  

V  

1

​  

=M  

2

​  

V  

2

​  

 

1×10=M  

2

​  

×1000

M  

2

​  

=  

1000

10

​  

 

M  

2

​  

=10  

−2

M

So, the correct option is B.