[20-2{5+(-12)}×{2(5-2-4)}]
Answers
Answered by
52
Here is your solution....
Using bodmas rule
B - brackets.
O - of .
D - division.
M - multiplication.
A - addition.
S - subtraction.
= [ 20 - 2 { 5 + ( -12 )} × { 2 ( 5 - 2 - 4 )}]
= [ 20 - 2 { -7} × { 2 ( 5 - 6 )}]
= [ 20 - 2 { -7} × { 2 ( -1)}]
= [ 20 - 2 { -7} × { -2}]
= [ 20+14×-2]
=[20+(-28)]
=[20-28]
=> -8
hope it helps you
Using bodmas rule
B - brackets.
O - of .
D - division.
M - multiplication.
A - addition.
S - subtraction.
= [ 20 - 2 { 5 + ( -12 )} × { 2 ( 5 - 2 - 4 )}]
= [ 20 - 2 { -7} × { 2 ( 5 - 6 )}]
= [ 20 - 2 { -7} × { 2 ( -1)}]
= [ 20 - 2 { -7} × { -2}]
= [ 20+14×-2]
=[20+(-28)]
=[20-28]
=> -8
hope it helps you
pam27:
good answer
Answered by
64
We will follow the BODMAS rule for solving this question:
B - brackets
O - of
D - division
M - multiplication
A - addition
S - subtraction
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Main Solution:
[ 20 - 2 { 5 + ( -12 )} × { 2 ( 5 - 2 - 4 )}]
[ 20 - 2 { 5 + ( -12 )} × { 2 ( 5 - 6 )}]
[ 20 - 2 { 5 + ( -12 )} × { 2 ( -1)}]
[ 20 - 2 { 5 + ( -12 )} × { -2}]
[ 20 - 2 { -7} × { - 2}]
[ 20 - 2 × 14 ]
[ 20 - 28 ]
=> -8
Hence, the final answer is -8.
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Thanks for the question!
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