Math, asked by aquib28, 8 months ago

20^2/5*6/9*7/2*4/2*3-65+95/5-65/95*65=​

Answers

Answered by dangerousqueen01
5

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 \frac{ {(20)}^{2} }{5}  \times  \frac{6}{9}  \times  \frac{7}{2}  \times  \frac{4}{2}  \times 3 - 65 + \frac{95}{5} -  \frac{65}{95}  \times 65 \\  =   \frac{20 \times 20}{5}  \times  \frac{6}{9}  \times  \frac{7}{2}  \times  \frac{4}{2}  \times 3 - 65 + \frac{95}{5} -  \frac{65}{95}  \times 65 \\  = 80 \times  \frac{2}{3}  \times  \frac{7}{2}  \times 2 \times 3 - 65 + 19 -  \frac{13}{19}  \times 65 \\  = 1120 - 65 + 19 -  \frac{845}{19}  \\  = 1120 - 84 -  \frac{845}{19}  \\  = 1036 -  \frac{845}{19}  \\  =  \frac{19684 - 845}{19}  \\  =  \frac{18839}{19}  \\   = 991\frac{10}{19}

Answered by Anonymous
2

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$$\begin{lgathered}\frac{ {(20)}^{2} }{5} \times \frac{6}{9} \times \frac{7}{2} \times \frac{4}{2} \times 3 - 65 + \frac{95}{5} - \frac{65}{95} \times 65 \\ = \frac{20 \times 20}{5} \times \frac{6}{9} \times \frac{7}{2} \times \frac{4}{2} \times 3 - 65 + \frac{95}{5} - \frac{65}{95} \times 65 \\ = 80 \times \frac{2}{3} \times \frac{7}{2} \times 2 \times 3 - 65 + 19 - \frac{13}{19} \times 65 \\ = 1120 - 65 + 19 - \frac{845}{19} \\ = 1120 - 84 - \frac{845}{19} \\ = 1036 - \frac{845}{19} \\ = \frac{19684 - 845}{19} \\ = \frac{18839}{19} \\ = 991\frac{10}{19}\end{lgathered}$$

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