Math, asked by tyagi0157, 8 hours ago

(20/27) ^4×(9/10) ^4×(2/3) ^4
solve this equation​

Answers

Answered by adityapalaria
4

Answer:

(20/27)^4= 10^4*2^4/9^4*3^4

(10^4*2^4/9^4*3^4)*(9^4/10^4)*(2^4/3^4)

ans=(2/3)^8

2^8=256

3^8=6561

256/6561

Similar questions