(20/27) ^4×(9/10) ^4×(2/3) ^4
solve this equation
Answers
Answered by
4
Answer:
(20/27)^4= 10^4*2^4/9^4*3^4
(10^4*2^4/9^4*3^4)*(9^4/10^4)*(2^4/3^4)
ans=(2/3)^8
2^8=256
3^8=6561
256/6561
Similar questions
Computer Science,
1 month ago
Math,
1 month ago
Accountancy,
2 months ago
Math,
2 months ago
English,
10 months ago
Physics,
10 months ago
English,
10 months ago