Math, asked by akhileshawrinakka, 8 months ago

20√3+5√27-2√12 and
find simplest form of √125 and √80​

Answers

Answered by RifaBorbora
3

Step-by-step explanation:

20 \sqrt{3}  + 5 \sqrt{27}  - 2 \sqrt{12}  \\  = 20 \sqrt{3}  + 15 \sqrt{3}  - 4 \sqrt{3}  \\  = 35 \sqrt{3}  - 4 \sqrt{3}  \\  = 31 \sqrt{3}

and,

 \sqrt{125}  \\  =  \sqrt{5 \times 5 \times 5}  \\  = 5 \sqrt{5}

and,

 \sqrt{80}  \\  =  \sqrt{2 \times 5 \times 2 \times 2 \times 2}  \\  = 2 \times 2 \sqrt{5}  \\  = 4 \sqrt{5}

Answered by biswajitdaskakdwip93
0

Answer:

20√3+ 5√3×3×3-2√3×2×2

20√3+5×3√3-2×2√3

20√3+15√3-4√3

35√3-4√3

31√3 ( answer)

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