Question

20-3(x-2)=27-6x+2(2x-1)​

Answer 1

Answer:

$20-3(x-2)=27-6x+2(2x-1)$, then $x=1$

Step-by-step explanation:

To solve:- $20-3(x-2)=27-6x+2(2x-1)$

 

                 $20-3(x-2)=27-6x+2(2x-1)\\ \\ 20-3x+6=27-6x+4x-2\\ \\ 20+6-3x=27-2+4x-6x\\ \\ 26-3x=25-2x\\ \\ -3x+2x=25-26\\ \\ -x=-1\\ \\ x=1$

Answer 2

As per the data given in the above question.

In the above question, it is given that,

The given data is 20-3(x-2)=27-6x+2(2x-1)​,

 We have to find the value in of the given equation.

Thus, simplifying we get,

$20-3(x-2)=27-6x+2(2x-1)\\20-3x+6=27-6x+4x-2\\26-3x=31-8x$

Shifting common terms one sides we get,

$-3x+8x=31-26\\5x=5\\x=\frac{5}{5}\\x=1$

Hence the value of x is equal to 1.