20*4=10,30*13=12, 10*12=3,40*11=?
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• Given:- 20*4=10,30*13=12, 10*12=3
• To find:- 40*11=?
• Solution:-
20×4=80 —› (as in 80 only two elements are present & 2³=8)—›8+0+2=10
30×13 = 390 —› (as three elements are present)—› 3+9+0=12
and
10×12=120 —› (as three elements are present)—› 1+2+0= 3
so according to the format
40×11= 440—›(as three elements are present)—› 4+4+0=8
So 20*4=10,30*13=12, 10*12=3,40*11=8
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