20] 4 car is speeding along a level road at 25 m/s. The brakes bring the 500 kg car to a speed of 3
m/s over a distance of 5 m. Determine the force by brakes and work done on the car by brakes
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initial velocity = 25m/s
final velocity = 3m/s
mass of car = 500 kg
distance = 5m
V² - u² = 2 a s
3² - 25² = 2 a 5m
9 - 625 = 10a
625 - 9 = 10a
root of 616
24.8 =10a
a = 2.48m/s²
F = MA
F = 500(2.48)
F = 1240N
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