Physics, asked by nomaan20, 8 months ago

20
a) A stone is dropped from a height 100 m and at the same time another one in projected vertically
upwands with a velocity of 100m/sec. find when & Where the two stones meer?
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a) What is relative aktun Explain it​

Answers

Answered by MrCookie
0

Answer:

the stone meet at a height of   20 m above the ground after 4 seconds.

Explanation:

Let the stones meet at point A after time t.

For upper stone  :            

u′=0         

x=0+21gt2

x=21×10×t2           

⟹x=5t2            ............(1)

For lower stone :            

u=25  m/s  

100−x=ut−21gt2

100−x=(25)t−21×10×t2           

⟹100−x=25t−5t2            ............(2)

Adding (1) and (2),  we get          

25t=100              

⟹t=4 s        

From (1),            

x=5×42                 

⟹x=80 m 

Hence the stone meet at a height of   20 m above the ground after 4 seconds.

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