Question

20. A bar magnet when placed at an angle of 30°
the direction of magnetic field induction of 5x10-5 T
experiences a moment of couple 2.5 x 10-6 N-m.
the length of the magnet is 5cm its pole strength
1) 2x10-2 Am 2 ) 5x10-2Am
3) 2A-m
4) 5A-m​

Answer 1

Explanation:

this

is

the

answer

of

ur

question

hope

u get

it

Answer 2

Answer:

2×10−2A−m  

5×10−2A−m

2A−m

5A−m

τ=MBsinθ⇒τ=(mL)Bsinθ

⇒25×10−6=(m×5×10−2)×5×10−2×sin30∘

⇒m=2×10−2A−m