Question

20. A block of mass 5 kg is placed on a horizontal surface with co-efficient of friction 1) = 0,2", then the
maximum and minimum value of force F for which the block remains at rest (g* 10 m/s)
15N 5 kg
ZZZZ
(A) 15 N, 10 N
(C) 10 N, 25 N
(B) 25 N, 5 N
(D) 5 N, 25 N​

Answer 1

Answer:

The max force needed would be the limitinɡ frictional force , which is

Lff=ʊR=0.2 x 5 x 10

=10N