20. A boat goes a certain distance downstream and then returns and
covers 40% of distance covered in downstream. Ratio of time taken in
covering downstream and upstream distances is 3 : 2. If speed of boat
in still water is reduced by 50% then it covers 60 km downstream in
10 hours. Find the speed of boat in still water.
(a) 9 km/hr
(b) 8 km/hr
(c) 6 km/hr
(d) 10 km/hr
(e) 12 km/hr
Answers
Solution:
Let speed of boat in still water be m km/hr
Let speed of boat currently be n km/hr
And as it is given that ratio of time taken in covering downstream and upstream distances is 3 : 2.
So , Let the time taken to cover the given distance in downstream and upstream be 3t hours and 2t hours
Now ,
40% of distance is covered in = 2t hours
100% of distance is covered in = 5t hours
According to question,
Now ,
So ,
(b) 8 km/hr is the correct answer.
The speed of boat in still water will be 8 km/hr.
Given :
Ratio of time taken in covering downstream and upstream distance is =3:2
Speed of boat in still water at downstream = 60 km
Time taken = 10 hours
Reduced speed of boat in still water covered by 50%
Return speed of downstream 40%
To find:
Speed of boat in still water =??
Solution :
Speed of boat in still water = x km/hr
Actual speed of boat = y km/hr
Speed of boat downstream = x-y
Total speed of boat = x+ y
Ratio of time taken
40% distance covered in 2t hr
Total distance covered in 3t + 2 t = 5t hr
5x-5y = 3x – 3y
After solving we get:
2x = 8y
= 4
Now
= 10
After doing simple calculation
Y= 2km/hr
And X= 8km/hr
So the speed of boat in still water = 8km/hr