20. A body of mass 5Kg is lifted vertically at a constant velocity of 12m.
calculate
a) the force applied
b) work done in lifting the body.
Answers
Answered by
0
Answer:
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Answered by
6
Answer:
Force, F = 49 N
Work done, W = 360 J
Explanation:
Given that,
Mass of the body, m = 5 kg
It is lifted vertically at a constant velocity of 12 m/s
(a) The force acting on the body is called gravitational force. The force applied is given by :
F = mg
F=5 kg×9.8 m/s
2
F=49 N
(b) The work done in lifting the body is given by :
W=
2
1
mv
2
W=
2
1
×5×12
2
W=360 J
(c) The work performed is stored in the form of energy.
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