Question

20. A cell of emf E internal resistance r is connected across an external
resistance R (R>>r). The p.d across R is

(a)E÷R+r
(b) E(1 -r÷R)
(e) E(1 +r÷R)
(d) E (R+r)
​

Answer 1

Answer:

sry I am not able to understand

Answer 2

Answer:

We know that I=

R+r

E

and V=IR

So V=

R+r

ER

…(I)

V=

1+

R

r

E

Here E, r are constants. So

V∝

1+

R

r

1

(from II)

and V∝R (from I)

With increase in R, P.D. across R is increased up to maximum value E.