Question

20 A graph for v - tof an object is shown below. 5 4.6 A 4 B 3 + Velocity (m/s) 2 1 1 O C + 1 2 3 4 5 6 7 8 9 10 11 12 Time (s)- 0 Identify the type of motion by line OA and BC. (i) What is the time duration during which the car moves with constant velocity? (iii) Calculate the acceleration between the 3rd and 10th second. (iv) What is the distance travelled in the first 10 s?​

Answer 1

Answer:

i) The motion represented by OA is accelerated motion while the motion represented by BC is decelerated motion.  

ii) Acceleration of the lift during first 2 seconds = 4.6 / 2 = 2.3 m/s2  

iii) Acceleration between third and tenth second = 0  

iv) Acceleration during last 2 seconds = 0 - 4.6/2 = - 2.3 m/s2

Explanation:

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