Question

20. A man walks 1 km towards East and then he turns to south and walks 5km.
Again he turns to East and walks 2 km, after this he
turns to North and walks 9km. Now ,how far is he from his starting point?

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Answer 1

Step-by-step explanation:

AE = 1+2= 3 km

EF = 9-5 = 4km

AF^2= AE^2 + FE ^2

AF = √ 9 + 16

AF = √ 25

AF = 5km

Answer 2

Step-by-step explanation:

ab 2+1=3

bc=9-5=4

ac=3×3+4×4

ac 9+16= √25

ac 5km

this is solve by Pythagoras