Question

20) A mass of 1000 kg having a speed of 10m/s is brought to
rest over a distance of 100m Find A) the retardation B)
The retarding force





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Answer 1

Answer:

A) the retardation is 0.5 ms⁻²

B) the retarding force is 500 N

Step-by-step explanation:

Given -

Mass(m)= 1000 kg

Initial Velocity(u) = 10 m/s

Distance travelled (s)= 100 m

Final velocity (v)= 0 m/s

According to third equation of motion,

v² = u² - 2as for retardation where -a is the retardation

0² = 10²- 2a(100)

0= 100 - 200a

200a = 100

a = 0.5

The retardation is 0.5 ms⁻²

A)0.5 ms⁻²

The force is given by m x a

m= 1000kg

a = 0.5 ms⁻²

Force = 1000 x 0.5 = 500 N

B) 500 N

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