20. A motorboat is in constant motion with a speed of of 40m/s. If the
resistance offered by water is 4000N then find the power of engine.
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=(4
i
−2
j
+
k
)ms
−1
F
=(5
i
−10
j
+6
k
)N
Power =
F
.
v
P=(4
i
−2
j
+
k
)⋅(5
i
−10
j
+6
k
)
Performing the dot product we get: 20+20+6=46 W
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