Question

20. A particle A of charge g placed near a un formily
charged infinite plane sheet with surface charge
density o experiences a force f. When this
particle is placed near an infinite metal plate with
surface charge density o, it experiences a force
Then equals to
(1) 1
(2) 2
(3)1/2
(4)3​

Answer 1

The ratio between the forces is 1/2.

Explanation:

The electric field due to a infinite plane sheet is

E1 = σ/ 2εo

Hence, the force experienced by a charge q placed near the sheet is

F1 = Eq1 = qσ/ 2εo

Now, the electric field due to a infinite metal plate is

E2 = σ/ εo

Hence, the force experienced by a charge q placed near the plate is

F2 = Eq2 = qσ/ εo

Therefore we get:

F1 / F2 = qσ/ 2εo x εo / qσ = 1/2

Hence the ratio between the forces is 1/2.

Also learn more

What is the force between two small charged spheres having charges of 2 × 10 −7 C and 3 × 10 −7 C placed 30 cm apart in air?

https://brainly.in/question/3741674

Answer 2

ans is C BRO....

the correct ans is 1/2

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