(20) A rectangular ceiling of a room has
length 18m. 75 cm broad paper costs
81 at the rate of 45 paise per sq.m. What
be breadth of the ceiling.
Answers
Answer
Given
- Length of rectangular ceiling of a room 18m
- Breadth of paper is 75 cm
- Cost of papering the ceiling is Rs 81 at the rate of 45 paise per sq.m
Find
- The breadth of the ceiling
Solution
- 1 cm = 1/100 m
- 75 cm = 0.75 m
- 1 rupees = 100 paise
- 81 rupees = 8100 paise
Let the breadth of the ceiling be 'B'
Area of ceiling
=> Length x Breadth
- Length = 18 m
- Breadth = B m
=> Aera = 18 x B
=> Area = 18B
Number of paper required to cover ceiling
=> 18B/0.75
Cost of covering the the ceiling with paper
=> 18B/0.75 x 45
Given that the cost of covering the wall with paper is Rs 81 or 8100 paise
=> 18B/0.75 x 45 = 8100
=> 18B x 45 = 8100 x 0.75
=> 18B x 45 = 6075
=>18B = 6075/45
=> 18B = 135
=> B = 135/18
=> B = 7.5 m
- Hence the breadth of ceiling is 7.5 m
Answer
Given
Length of rectangular ceiling of a room 18m
Breadth of paper is 75 cm
Cost of papering the ceiling is Rs 81 at the rate of 45 paise per sq.m
Find
The breadth of the ceiling
Solution
1 cm = 1/100 m
75 cm = 0.75 m
1 rupees = 100 paise
81 rupees = 8100 paise
Let the breadth of the ceiling be 'B'
Area of ceiling
=> Length x Breadth
Length = 18 m
Breadth = B m
=> Aera = 18 x B
=> Area = 18B
Number of paper required to cover ceiling
=> 18B/0.75
Cost of covering the the ceiling with paper
=> 18B/0.75 x 45
Given that the cost of covering the wall with paper is Rs 81 or 8100 paise
=> 18B/0.75 x 45 = 8100
=> 18B x 45 = 8100 x 0.75
=> 18B x 45 = 6075
=>18B = 6075/45
=> 18B = 135
=> B = 135/18
=> B = 7.5 m
Hence the breadth of ceiling is 7.5 m