Math, asked by itzsehaj, 5 hours ago

20. A rectangular metal sheet of length 44 cm and breadth 11 cm is folded along its length to form a cylinder. Find its volume.
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Answers

Answered by shrishti769
3

Answer:

1694m^{3}

Step-by-step explanation:

Given that length of sheet= 44m and breadth = 11 m .

As sheet is rolled along length, so length of sheet becomes circumference of the cylinder and its breadth is converted into height of cylinder.

2π r= 44 m, 2x22xr/7 = 44, r = 7 m and h= 11 m

Volume of cylinder =2πrh = 22 x 7 x7 x11/7 = 22 x 77 = 1694m^{3}

Answered by OoAryanKingoO78
4

Answer:

The volume of the cylinder is 2772 cm³

Step-by-step explanation:

Let the radius be =   r

We know that the length of the sheet = circumference of the circle

Height of the cylinder = 18 cm

44 = 2r

2 x 22/7 r = 44

r = (44 x 7) / (22  x 2)

r = 7 cm

Volume of cylinder = r^2 .h

=22/7 × 7 × 7 × 18

= 2772 cm³

The volume of the cylinder is 2772 cm³.

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