Question

20. A room is 8 m long, 7.6 m wide and 3.5 m high. The walls are to be distempered, allowing 25 m² doors, windows, etc. Find the total area to be distempered.



length of room = 8m
width of room. =7.6m
height of room=3.5m

Wall are to be distempered, allowing 25m²

area of wall =2(8m+7.6m)×3.5m
=(16 m+15.2m)×3.5m
=109.2m²
area of wall-area of wall are to be distempered


109.2m²-25m²=84.2m²

answer =84.2​

Answer 1

Answer:

Step-by-step explanation:

Total area of the 4 walls = ( 8 + 7.6 + 8 + 7.6) x 3.5 = 109.2 m²

Area without the doors and windows = 109.2 - 25 = 84.2 m²

Answer: 84.2 m²

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Answer 2

Answer:

The Total area of walls to be distempered = 84.2$m^{2}$

Step-by-step explanation:

The Area of four walls of a cuboid with length (l), width(b), and height(h) is given by 2(l+b)h.

Given,

• Length of the room = l = 8m

• Width of the room = b = 7.6m

• Height of the room = h =3.5m

Walls are to be distempered with doors and windows = 25$m^{2}$

Area of the four walls = 2(l+b)h

                                    = 2×(8+7.6)×3.5

                                    = 2×15.6×3.5

                                    = 109.2$m^{2}$

• The Total area of walls to be distempered = Area of four walls - Area of walls distempered with doors and windows

                                                  = 109.2 - 25

                                                  = 84.2$m^{2}$

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