Question

20. A sum of money was lent at simple
interest at 11% p.a. for 3/2 years and 4%2
years respectively. If the difference in
interest for two periods was Rs. 41250, the
sum is.
a. Rs. 3250
b. Rs. 3500
c. Rs. 3750
d. Rs. 4250
e. None of These​

Answer 1

Answer:

(e) none of the above

Step-by-step explanation:

Let the Equal Sum of money be Rs. x⠀

First Part :-

principal = x rupees

rate= 11% pa

time = 3/2 years= 1.5 years

Second part :-

principal = x rupees

rate = 4 %

time = 2 years

__________________________________________________________

difference = Sl1- Sl2

difference = PRT1/100 - PRT2/100

41250 = X×11×1.5/100 - X×4×2/100

41250 = 16.5x/100 - 8x/100

41250 = [16.5x - 8x]/100

41250 = 8.5x/100

x/100 = 41250/8.5

4852.94117647 = x/100

x = 4852.94117647×100

x = 58294.117647 (e)