Question

20. A train starts from rest and accelerate uniformly at the rate of 5 m/s2 for 5 sec. Calculate the velocity of
train in 5 sec.
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Answer 1

Answer:

v -25 m/s

Explanation:

v-0 a-5m/s2 ,t -5 sec, v-u+at, v = 0+5*, v= 25 m/s

Answer 2

Answer:

GIVEN :-

Initial velocity , v = 0 m/s. [Train starts from rest]

Time , t = 5 seconds.

Acceleration , a = 5 m/s².

TO FIND :-

The Final velocity , v.

SOLUTION :-

$\\ \bigstar \underline{ \displaystyle \sf \: Third \: Equation \: Of \: Motion.}$

$: \implies\displaystyle \sf \: v = u + at.$

v = Final velocity.

u = initial velocity.

a = Acceleration.

t = Time taken.

$\\ : \implies\displaystyle \sf \: v = 0 + 5 \times 5$

$: \implies\displaystyle \sf \: v = 0 + 25$

$: \implies \underline{ \boxed{\displaystyle \sf \: v = 25 \: ms ^{ - 1} }}$

$\therefore \underline{ \displaystyle \sf \: Velocity \ of \ train \ in \ 5 \ second \ is \ 25 m/s.}$

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$\dashrightarrow \displaystyle \sf Equation \ of \ motion_{(1)} = v = u + at.$

$\dashrightarrow \displaystyle \sf Equation \ of \ motion_{(2)} = s = ut + \dfrac{1}{2} at^{2}$

$\dashrightarrow \displaystyle \sf Equation \ of \ motion_{(3)} = v^{2} - u^{2} = 2as$