Question

20. A train travelling with a speed 60 km/h
catches another train travelling in the
same direction and then leavers it 120 m
behind in 18s. The speed of the second
train is​

Answer 1

Explanation:

Let speed of the 2nd train is S m/sec.

And,

60 kmph =60×518=503

m/sec.

As trains are traveling in same distance, Then Relative distance,

=60×518=503503−S=12018⇒50−3S3=203⇒50−3S=20⇒3S=50−20⇒3S=30∴S=10m/sec

Or, Speed of the 2nd train = 10×185

= 36 kmph.