20. A train travels at 60 km/hr for 0.52 hr; at 30 km/hr for the next 0.24 hr and at 70 km/hr
for the next 0.71 hr. What is the average speed of the train?
Answers
Answered by
2
hope it may help u nikki my frnd and pls reply
here , total dist = speed x time
so , d = (60 x 0.52) + (30 x 0.24)+( 70 x 0.71)
=>d= 88.1 km
here ,total time taken will be
t= 0.52+0.24+0.71 = 1.47 hrs
wkt , average speed = d/t
=> 59.932 = 60 km/hr
here , total dist = speed x time
so , d = (60 x 0.52) + (30 x 0.24)+( 70 x 0.71)
=>d= 88.1 km
here ,total time taken will be
t= 0.52+0.24+0.71 = 1.47 hrs
wkt , average speed = d/t
=> 59.932 = 60 km/hr
9034621146:
both r same but methods r different so pls talk to me
Answered by
2
Distance travelled in the 1st interval
=60 × 0.52=31.2km
Distance travelled in the 2nd interval
=30×0.24=7.2km
Distance travelled in the 3rd interval
=70×0.71=49.7km
Total distance travelled =88.1km
Total time taken to cover that distance = 1.47hr
So avg speed
= 88.1/1.47=59.93km/hr = 60 km/hr (approx)
Hope it helps..... :-)
=60 × 0.52=31.2km
Distance travelled in the 2nd interval
=30×0.24=7.2km
Distance travelled in the 3rd interval
=70×0.71=49.7km
Total distance travelled =88.1km
Total time taken to cover that distance = 1.47hr
So avg speed
= 88.1/1.47=59.93km/hr = 60 km/hr (approx)
Hope it helps..... :-)
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