Math, asked by hardik24neema, 2 months ago

20. A vessel is filled with liquid, 3 parts of which are
water and 5 parts syrup. How much of the mixture
must be drawn off and replaced with water so that
the mixture may be half water and half syrup?
a.1/3
b.1/4
c.1/5
d.1/7



How 8/5*1/8 at last?​

Answers

Answered by savitar07
0

Answer:

c. 1/5

Step-by-step explanation:

let liquid replaced by water be x liters.

quantity of water in new mixture=(3-3x/8+x)

quantity of syrup in new mixture=(5-5x/8)

(3-3x/8+x)=(5-5x/8)

by solving this we get,

5x+24=40-5x

10x=16

x=16/10=8/5

so, part of mixture replaced=8/5*1/8

                                             =1/5

Answered by cellreferencec
0

Answer:

20. A vessel is filled with liquid, 3 parts of which are

water and 5 parts syrup. How much of the mixture

must be drawn off and replaced with water so that

the mixture may be half water and half syrup?

a.1/3

b.1/4

c.1/5

d.1/7

How 8/5*1/8 at last?

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