Question

(20)
AC = DB Prove that
о
B
condition.
(ii) Is OA= OB? Why?
8. In the given figure, ACI AB, DBI AB and
(i) AOACE AOBD, write the congruency​

Answer 1

Given ∠AOB=∠COD

∠AOB−∠COB=∠COD−∠COB

∴∠AOC=∠DOB

In ΔAOC and ΔDOB

i)OA=OB(Given)

ii)OC=∠OD (Given)

iii)∠AOC=∠DOB (Proved above)

∴ΔAOC≅∠DOB

(SAS Axiom)

∴AC=BD

Answer 2

Answer:

Here you go

Dont copy in online exams since they are bad

Step-by-step explanation:

Given ∠AOB=∠COD

∠AOB−∠COB=∠COD−∠COB

∴∠AOC=∠DOB

In ΔAOC and ΔDOB

i)OA=OB(Given)

ii)OC=∠OD (Given)

iii)∠AOC=∠DOB (Proved above)

∴ΔAOC≅∠DOB

(SAS Axiom)

∴AC=BDnt